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Find the exact value of sin(θ) for an angle θ with sec(θ) = 5/2 and with its terminal side in Quadrant IV.



Find the exact value of sin(θ) for an angle θ with sec(θ) = 5/2 and with its terminal-example-1
User Yesnik
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2 Answers

4 votes

Answer:

B

Explanation:

(Sorry about the crude drawing)

The drawing shows what the triangle with a terminal side in Quadrant IV looks like.

Secant is the ratio of the hypotenuse to the adjacent side of the angle. In the given ratio, we can set 5 as the hypotenuse and 2 as the adjacent side (you can see them labeled in the picture).

Now, we want to find sin, which is (opposite)/(hypotenuse). However, we don't know the opposite. We can find it by using the Pythagorean Theorem:


√(5^2-2^2) =√(25-4) =√(21)

So, the opposite side is
√(21). But, we see that since it's in the fourth quadrant, it must be negative, so we have opposite =
-√(21). Now, we can find the ratio because hypotenuse = 5:

sin(θ) =
-√(21) /5.

Thus, the answer is B.

Hope this helps!

Find the exact value of sin(θ) for an angle θ with sec(θ) = 5/2 and with its terminal-example-1
User Zvi Karp
by
4.1k points
5 votes

Answer:

Option B

Explanation:

Please see attached picture for full solution.

Y has to be negative since it lies below the x axis.

In 4th quadrant, only the cosine of an angle is positive.

Find the exact value of sin(θ) for an angle θ with sec(θ) = 5/2 and with its terminal-example-1
User Waypoint
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4.2k points