376,238 views
40 votes
40 votes
Find the distance between (1, 1) and (3, 4).

User Ccgillett
by
2.9k points

2 Answers

18 votes
18 votes

Answer:

3.61

Explanation:

length=
\sqrt{(x_(2)-x_(1) )^(2)+(y_(2)-y_(1) )^(2) )}

=
\sqrt{(3_{}-1_{} )^(2)+(4_{}-1_{} )^(2) )}

= 3.61

User Aloisdg
by
3.2k points
14 votes
14 votes

Answer:

√13

Explanation:

Let,

( x1, y1 ) = ( 1, 1 )

Here,

x1 = y1 = 1

( x2, y2 ) = ( 3, 4 )

Here,

x2 = 3

y2 = 4

Formula : -

( Distance )² = ( x2 - x1 )² + ( y2 - y1 )²

( Distance )² = ( 3 - 1 )² + ( 4 - 1 )²

= 2² + 3²

= 4 + 9

( Distance )² = 13


Distance = √13

User Talles
by
2.7k points