Question

12. Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.1 kg attached to it and has a length of 5 m. Pendulum 2 has a ball of mass 0.5 kg attached to a string of length 1 m. How does mass of the ball affect the frequency of the pendulum? Which pendulum will have a higher frequency and why?

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Answer 1

According to Hooke 's law

`\\ \rm\rightarrowtail \\u=k\sqrt{(\ell)/(m)}`

`\\ \rm\rightarrowtail \\u\propto (1)/(√(m))`

Hence lower the mass higher the frequency

• First ball will have a higher frequency