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What is the probability of obtaining prime numbers when a fair dice is thrown?

User Ruhm
by
5.4k points

2 Answers

6 votes

Answer:

2/3

Explanation:

1 2 3 5 are prime numbers. that 4/6 which is 2/3

User Timothy Klim
by
5.5k points
5 votes

Answer:

probability: 4/6 = ~66.67%

simplified: 2/3

Explanation:

Prime numbers are numbers that cannot be factored into smaller natural numbers (whole numbers).

In a ordinary cube, there are 6 sides, numbered 1 - 6. Find the factors of each number:

1: 1

2: 1 ,2

3: 1 , 3

4: 1 , 2 , 4

5: 1 , 5

6: 1 , 2 , 3 , 6

If there is any number with only 1 and the number itself, then it is a prime number. In this case, it will be 1, 2, 3, 5, or 4 sides in all.

4/6 is your probability of rolling a prime number for a fair dice.

Most likely, you will need to simplify. Divide 2 from both numerator & denominator:

(4/6)/(2/2) = 2/3

2/3 is your simplified answer.

User Jukka Suomela
by
4.6k points
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