Question

A 200-turn solenoid having a length of 25 cm and a diameter of 10 cm carries a current of 0.29 A. Calculate the magnitude of the magnetic field B inside the solenoid

Answer 1

Hi there!

We can use the following equation to calculate the magnetic field inside of a solenoid:

`B = \mu_0 ni`

B = Magnetic Field Strength (T)
n = number of loops PER LENGTH

i = current through solenoid (A)
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)

First, we can solve for 'n' given 'N' (total # of loops) and L (length of solenoid).

`n = (N)/(L) = (200)/(0.25) = 800`

Now, we can calculate the magnetic field:

`B = (4\pi * 10^(-7)) (800)(.29) = \boxed{2.915 * 10^(-4) T}`