Question

Which are solutions of x2 5x = 2? check all that apply. startfraction 5 over 2 endfraction startfraction startroot 33 endroot over 4 endfraction startfraction 5 over 2 endfraction startfraction startroot 33 endroot over 2 endfraction startfraction 5 over 2 endfraction minus startfraction startroot 33 endroot over 2 endfraction startfraction negative 5 over 2 endfraction minus startfraction startroot 33 endroot over 2 endfraction startfraction negative 5 over 2 endfraction startfraction startroot 33 endroot over 2 endfraction

Answer 1

C and D

Explanation:

correct on edge

Answer 2

x = -5/2 + root(33)/2 or x = -5/2 - root(33)/2

Explanation:

ok so your computer is

saying:

x^2 + 5x = 2

and takes the 5 divides it by 2 and squares the result

x^2 + 5x + 25/4 = 2 + 25 /4 but then replaces a trinomial with a binomial

(x + 5/2)^2 = 2 + 25/4 = 33/4

solving

x = -5/2 + root(33/4) or x = -5/2 - root(33/4)

or

x = -5/2 + root(33)/2 or x = -5/2 - root(33)/2