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4 votes
Solve for the missing length and the other two angles in the triangle below

Solve for the missing length and the other two angles in the triangle below-example-1
User Mkell
by
5.4k points

1 Answer

4 votes

Answer:

AC = 3.72 units

Angles:

A = 132.6°

C = 27.4°

Explanation:

AC² = 5² + 8² - 2(5)(8)cos(20)

AC² = 13.82459034

AC = 3.718143399

3.718143399/sin20 = 8/sinA

sinA = 0.7358944647

A = 180 - 47.38285134

A = 132.6171487

3.718143399/sin20 = 5/sinC

sinC = 0.4599340405

C = 27.38285134

User XLite
by
5.2k points
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