Question

Question 2 (5 points)

(03.03, 03.06 MC)
What is the equation of the line that passes through the points (-2, 3) and (2, 7)? (5 points)
оа
x-y=-1
Ob
X-y=-2
Ос
x - y = -5
Od
X-y= -6

Answer 1

`x - y + 5 = 0`

Explanation:

Given:

• Line passes through (-2,3) and (2,7)

Required:

• Find the equation of the line

The equation of the line passing through two points is given by

`(y-y_(1) )/(y_(2)- y_(1) ) =\frac{x_{}- x_(1) }{x_(2) -x_(1) }`

So,
`(y-3)/(7-3) =(x-(-2)))/(2-(-2))`

`(y-3)/(4) =(x+2)/(2+2)`

`(y-3)/(4) =(x+2)/(4)`

Now,
`y-3 = x+2`

On rearranging,

`x - y + 3 + 2 = 0x - y + 5 = 0`

Therefore, the equation of the line is
`x - y + 5 = 0.`