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Question 2 options: A fence must be built to enclose a rectangular area of 45,000 ft2. Fencing material costs $4 per foot for the two sides facing north and south and $8 per foot for the other two sides. Find the length and width that will produce the least expensive fence.

User Technowise
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1 Answer

2 votes

Answer:

The length that would produce the least expenses is
A= 300 ft

The width that would produce the least expenses is
B= 150 ft

Explanation:

From the question we are told that the

Required area to enclose is
A = 45,000 ft^2

Fencing material cost is
C =$4 per foot for north and south

Fencing material cost for east and west
C_(E/W) = $8

The diagram for this question is shown on the first uploaded image

From the diagram is mathematically evaluated as

AB = 45000

=>
B = (45000)/(A)

The overall cost of building this fence is


T = 2 A (4) + 2(B)(8)

Substituting for B in the equation above


T = 8A +16 ((45000)/(A) )

differentiating both sides with respect to x


T' (A) = 8 - (16 *45000)/(A^2)

At minimum possible cost
T'(A) = 0

=>
8 - (16 *45000)/(A^2) = 0


8A^2 = 16*45000


A^2 = (16*45000)/(8)


A = \sqrt{( 16*45000)/(8) }


= 300 ft

Then B is mathematically evaluate as


B = (45000)/(300)


= 150 ft

Then the maximum is mathematically evaluated as


T = 8 (300) + 16(150)

=$4800

Question 2 options: A fence must be built to enclose a rectangular area of 45,000 ft-example-1
User Generalhenry
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