Answer:
150 adult tickets, 80 student ticket and 48 senior tickets.
Explanation:
Given:
A theater has tickets priced at $6 for adults, $3.50 for students, and $2.50 for seniors.
A total of 278 tickets were sold for one showing with a total revenue of 1300.
If the number of adult tickets sold was 10 less than twice the numbers of student tickets.
Question asked:
How many of each type of ticket were sold?
Solution:
Let the number of students tickets sold =
![x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/p9sq9b3rc5nwoqzhzc8wcaj51b36281l9g.png)
Then the number of adult tickets sold =
![2x-10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5nlw7h7e0mxkf3m6kkjle6nv41dj26qmy9.png)
Then the number of senior tickets sold =
![278-(x+2x-10)=278-(3x-10)=278-3x+10=288-3x](https://img.qammunity.org/2021/formulas/mathematics/high-school/ci2yrg4gwpke8m42vxen9sf98csbrc0eqx.png)
Total revenue = $1300
![3.5* x+6(2x-10)+2.5(288-3x)=1300\\ \\ 3.5x+12x-60+720-7.5x=1300\\ \\ 8x+660=1300\\ \\ Subtracting\ both\ sides\ by\ 660\\ \\ 8x=640\\ \\ Dividing\ both\ sides\ by\ 8\\ \\ x=80](https://img.qammunity.org/2021/formulas/mathematics/high-school/203ctac5mdto1rgawe3ojopiuxse0taap7.png)
The number of students tickets sold =
= 80
The number of adult tickets sold =
=
![2*80-10=160-10=150](https://img.qammunity.org/2021/formulas/mathematics/high-school/5452dq8enjodccvw6puv9yzr6hd0s25w5k.png)
The number of senior tickets sold =
![288-3x=288-3*80=288-240=48](https://img.qammunity.org/2021/formulas/mathematics/high-school/d4s1jhb8cfyl118qmxj0czwe9iysv7a9rr.png)
Therefore, 150 adult tickets, 80 student ticket and 48 senior tickets are sold.