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How many integers between 0 and 4n (inclusive) must you pick in order to be certain

that at least one of them is odd?

User Bajlo
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1 Answer

2 votes

Answer:

2n+1 integers

Explanation:

There are
(4n)/(2) + 1 = 2n + 1 even integers (0 inclusive) and
2n odd integers between 0 and 4n.

Worst case scenerio: pick all
2n+1 even integer before picking an odd integer.

Therefore, to pick at least one odd integer, one might pick
2n + 1 even integers + 1 odd integer =
2n+2 integers.

User Will Buffington
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