Question

at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a pressure of 0.612 atm and a temperature of 28.0c

Answer 1

initial temperature=
`-3.31^(\circ)C`

Step-by-step explanation:

Assuming that the given follows the ideal gas nature;

`P_1=0.723atm`

`V_1=13.5L`

`T_1=?`

`P_2=0.612atm`

`V_2=17.8L`

`T_2=28 ^(\circ)C =273+28K=301K`

mole of gass will remain same at any emperature:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

putting all the value we get:

`T_2 =269.7K =-3.31 ^(\circ) C`

initial temperature=
`-3.31^(\circ)C`