Question

Find the product of (4z2 + 7z – 8) and (–z + 3).

Answer 1

(4z2+7z−8)(−z+3)

=(4z2+7z+−8)(−z+3)

=(4z2)(−z)+(4z2)(3)+(7z)(−z)+(7z)(3)+(−8)(−z)+(−8)(3)

=−4z3+12z2−7z2+21z+8z−24

=−4z^3+5z^2+29z−24