Answer:
784 g.
Step-by-step explanation:
Since 1 mole of gives us 2 moles of $Fe$, 7 moles $Fe_2O_3$ will give us 14 moles of $Fe$
Molar mass of $Fe$= 56 g/mol
Thus, mass of 14 moles is $14 \times 56= \boxed{784}$
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