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What is the equation of the line that passes through the point (-2, -2) and is perpendicular to the line y = 2x+5

What is the equation of the line that passes through the point (-2, -2) and is perpendicular-example-1
User Kevinhyunilkim
by
2.8k points

2 Answers

16 votes
16 votes

Answer:

y = -1/2(x) - 4

Explanation:


y=-(1)/(2)(x)-4

User Ben Sewards
by
2.7k points
13 votes
13 votes

product of two perpendicular line slopes must equals - 1 ;

As you know the coefficient of x is the slope of the line

Thus if we suppose that line has a slope of m , we have :

m × 2 = - 1

m = - 1 / 2

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y = ax + b

y = - 1 / 2 x + b

The line passes through the point ( - 2 , - 2 ) thus :

- 2 = - 1 /2 × ( - 2 ) + b

- 2 = 1 + b

b = - 3

__________________________________

y = - 1/2 x - 3

Which mean the option c is the correct answer.