Question

A total of 2.00 mol of a compound is allowed to react with water in a foam coffee cup and the reaction produces 150 g of solution. The reaction caused the temperature of the solution to rise from 21.00 to 24.70 ∘C. What is the enthalpy of this reaction?

Answer 1

The Enthalpy of the reaction ΔH = 0.945
`(KJ)/(mole)`

Step-by-step explanation:

Given data

Mass = 0.15 kg

Change in temperature = 24 - 21 = 3 °c

Enthalpy of the solution is given by

ΔH = m
`C_(p)` ΔT

ΔH = 0.15 × 4.2 × 3

ΔH = 1.89 KJ

Enthalpy change per mole

ΔH =
`(1.89)/(2)`

ΔH = 0.945
`(KJ)/(mole)`

Therefore the Enthalpy of the reaction ΔH = 0.945
`(KJ)/(mole)`