30.7k views
2 votes
PLEASE HELP! 56 POINTS!

Wild-type Arabidopsis has five chromosomes (2n = 10). Trisomic plants are designated as Tr followed by the trisomic chromosome number—that is, Tr1 is trisomic for chromosome 1. Assuming that trisomy is fully viable and that all possible pairing configurations (including nonpairing) are possible at meiosis, what proportion of the progeny from the cross Tr1 × Tr1 will have a wild-type chromosomal complement?

1 Answer

3 votes

Answer:

Hi Presley! Hopefully this helps! If it doesn't, let me know!

Step-by-step explanation:

Answer: 1/9.

User Peter Cardona
by
4.3k points