Question

Find the coordinates of the turning point for the equation of the graph below

y=x^2– 16x +39
=

Answer 1

Explanation:

comparing given equation with ax^2+bx+c;

a=1 b=-16 c=39

now,

x coordinate of vertex = -b/2a

= 16/2*1

= 8

again,

y coordinate of vertex = (8)^2-16(8)+39

=-25

Therefore, the turning point is (8,-25).

Answer 2

x = 8 - sqrt(y + 25)

Explanation: