Answer:
b. 40 degrees
Step-by-step explanation:
Range = (U²Sin2tita)/g
Let's assume a constant velocity of 1 m/s and acceleration of 10 m/s² and try the following angles.
For 10 degree
Range= (sin20)/10
Range = 0.034m
For 40 degrees
Range= sin80/10
Range = 0.098m
For 70 degrees
Range = sin140/10
Range = 0.064
For 90 degrees
Range = sin180/10
Range = 0
Comparing the above result, we can see the degree with the highest range is degree 40.