Answer:

$sum\ or\ interior\ angles$

$ol\ pentagon\ is\ 540\textdegree.$

Explanation:

$Given\ of\ Pentagon$

$To\ hind\ o\ sum\ of\ Interiur\ angle\ of$

pentagon.

solutiono

$sum\ of\ the\ interior$
$angler\ of\ a\ pentajon$

$can\ be\ round\ by\ 1\ st$

$dividing\ it\ into\ triangler$

$from\ 1\ verter.$

$\therefore\ There\ are\ 3\ Triangles\ made.$

$sum\ of\ interiar\ angler\ or\ Triangles\ is$

$180\textdegree.\ Tmere\ are\ 3\ Triangles.$

$\therefore \ \ \ \ \ 180* 3=540\textdegree.$

$Hence\ sum\ ot\ interior\ angles$

$ol\ pentagon\ is\ 540\textdegree.$

I hope this helps you

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