193k views
5 votes
Suppose that a survey asks a random sample of 1500 adults in Ohio if they support an increase in the state sales tax. Suppose that 40% of all adults in Ohio support the increase. We independently select 7 adults at random and record their status in supporting the increase. What is the probability that exactly 4 people support the increase in tax?

a. 0.2419
d. 0.4838
b. 0.5162
c. 0.1935

User Ghoul
by
8.2k points

1 Answer

6 votes

Answer:

Option D) 0.1935

Explanation:

We are given the following information:

We treat adults in Ohio support the increase as a success.

P(Adults in Ohio support the increase) = 40% = 0.4

Then the number of adults follows a binomial distribution, where


P(X=x) = \binom{n}{x}.p^x.(1-p)^(n-x)

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 7

P(exactly 4 people support the increase in tax)


P(x = 4)\\\\= \binom{7}{4}(0.40)^4(1-0.40)^3\\\\= 0.1935

0.1935 is the probability that exactly 4 out of 7 adults in Ohio suppert the increase.

Thus, the correct answer is

Option D) 0.1935

User Adriano Silva
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories