Question

A rowing team rowed 50 miles while going with the current in the same amout of time as it took to row 25 going against the current. The rate of the current was 2 miles per hour. Find the rate of the rowing team in still water.

Answer 1

The rate of rowing team in still water is = 6
`(mi)/(hr)`

Step-by-step explanation:

Let speed of the team in still water = u
`(mi)/(hr)`

speed of the current = v
`(mi)/(hr)`

Upstream velocity = u - v

Downstream velocity = u + v

Given that

Distance covered in downstream is twice the Distance covered in upstream.

`(50)/(u + v) = (25)/(u - v)`

`(2)/(u + v) = (1)/(u - v)`

`2 u - 2 v = u + v\\`

u = 3 v

Rate of current (v) = 2
`(mi)/(hr)`

u = 3 × v = 3 × 2

u = 6
`(mi)/(hr)`

Therefore the rate of rowing team in still water is = 6
`(mi)/(hr)`