Question

What is the pressure, in atmospheres, of 14.3 moles of a gas at a temperature of 485 K in a 187 liter container?

P
V
=
n
R
T


R = 0.0821
a
t
m
⋅
L
m
o
l
⋅
K

Answer 1

3.04 atm

Step-by-step explanation:

First note r is in l*atm/mole*K

PV=nRT

P = nRT/V = 14.3(.0821)(485)/187 = 3.04 atm