Answer:
concentration in mole per litre=0.34mol/L
Step-by-step explanation:
5H2O2 + 2KMnO4 + 3H2SO4 ----> 5O2 + 2MnSO4 + 8H2O + K2SO4
H2O2 gives Oxygen gas on oxidation
First calculate the n-factor to calculate the normality
write the oxidation number of oxidizing and reducing molecule both side:
product side:
Oxidizing molecule:
O=-1
reducing molecule:
Mn=+7
product side:
O=0;
Mn=+2
n-factor of H2O2=2×(0-(-1))=2
n-factor of H2O2=2;
n-factor of KMnO4=7-2=5
n-factor of KMnO4=5;
molarity of KMnO4 =0.145M
Normality=Molarity × n-factor
normality of KMnO4=0.145 ×5=0.725
normality of KMnO4=0.725
Volume of KMnO4=46.9 ml
Volume of H2O2=50 ml
Lets assume normality of H2O2=N
mili equivalent=volume in ml × normality
mili equivalent of H2O2=mili equivalent of KMnO4
N×50=0.725×46.9
N=0.68
concentration in mole per litre means molarity
molarity=normality/n-factor
molarity=0.68/2
molarity=0.34mol/L
concentration in mole per litre=0.34mol/L