Answers :
Step-by-step explanation:
Given that.
First cylinder data
Inertial I₁ = 2.4 kgm²
angular speed ω₁ = 5.8 rad/s.
Second cylinder data
inertia I₂ = 1.3 kgm²
angular speed ω₂ = 7.0 rad/s.
If the cylinders couple so they have the same rotational axis, what is the angular speed of the combination (in rad/s)?
So, the cylinder couple and move together with the same angular speed
Then, using conservation of angular momentum
L(final) = L(initial)
(I₁ + I₂) • ω = I₁•ω₁ + I₂ω₂
(2.4+1.3)•ω = 2.4 × 5.8 + 1.3 × 7
3.7•ω = 23.02
ω = 23.02 / 3.7
ω = 6.22 rad/s
The combine angular speed of the cylinder is 6.22 rad/s