Answer:
z= -2.93
|z| = |-2.93|=2.93there fore we accepted Alternative hypothesis
The calculated z =2.93 > 1.6 the tabulated value at 89% level of significance.
A school social worker is interested in testing the claim that less than 89% of teenagers graduate from high school.
Explanation:
Step(i)
Given sample of 380 teenagers and 320 of them graduated from high school
The proportion of sample is
![p = (320)/(380) = 0.842](https://img.qammunity.org/2021/formulas/mathematics/college/s45zpafmu1kakvrrjkj54d0ktumy6hs1vj.png)
Given a school social worker is interested in testing the claim that less than 89% of teenagers graduate from high school
The population proportion 'P' = 0.89
Null hypothesis:- H₀: p= 0.89
Alternative hypothesis: H: p< 0.89
Step(ii)
The test statistic
![Z = \frac{p-P}{\sqrt{(PQ)/(n) } }](https://img.qammunity.org/2021/formulas/mathematics/college/gri039cbfjiu2664pfrx3i0phccrtq49r7.png)
![Z = \frac{0.84210-0.89}{\sqrt{(o.89X0.11)/(380) } }](https://img.qammunity.org/2021/formulas/mathematics/college/2s01yq9qbl1a3ujw3s2hjgxq83pm5l2t60.png)
on calculation , we get
![z = (-0.047894)/(0.016049)](https://img.qammunity.org/2021/formulas/mathematics/college/x8u78f1e1eayy1kybjugsf93pgq3foluy8.png)
z = -2.93
|z| = |-2.93|=2.93
we will use 89% of level of z- score =1.6 (check normal diagram)
The calculated z =2.93 > 1.6 the tabulated value at 89% level of significance.
we rejected null hypothesis
we accepted alternative hypothesis
Conclusion:-
A school social worker is interested in testing the claim that less than 89% of teenagers graduate from high school.