Question

The free energy change for the following reaction at 25 °C, when [Cd2+] = 1.20 M and [Fe2+] = 1.40×10-3 M, is -23.9 kJ: Cd2+(1.20 M) + Fe(s) Cd(s) + Fe2+(1.40×10-3 M) ΔG = -23.9 kJ What is the cell potential for the reaction as written under these conditions? Answer: -24.07 V Would this reaction be spontaneous in the forward or the reverse direction?

Answer 1

It's spontaneous in the reverse direction

Step-by-step explanation:

A negative voltage indicate s that the reverse reaction is spontaneous (i.e. oxidation at the cathode, and reduction at the anode; by convention you would need to swap the labels on the electrodes)