Question

To find the width of a river,a boy places a wooden peg at a point A on one side directly opposite of an object B on the opposite bank.From A,he walks 50m

along the bank to a point C. He observes that angle ACB =34 degree.Calculate the width of the river.

Guys please help me ​

Answer 1

27.96m

This resembles a triangle(a right angled triangle in fact!)

If ACB is 34 and AC is 50, we must use trigonometry.

Here we should be using cosine

SOH

CAH

TOA

Cosine = Adjacent/Hypotenuse

Adjacent = BC = x

Hypotenuse = AC = 50

cos(x/50) = 34

Using a calculator,

x = 41.45

Now we should be finding the width of the river ( Line AB)

50² - 41.45² = 781.8975

√781.8975 ≈ 27.96

Thus, width of river is 27.96 cm

Answer 2

33.7 m

Explanation:

tan ACB = AB/AC

tan 34 = AB/50

AB = 50tan(34)

AB = 33.7254258421