Answer: 0.55L
Step-by-step explanation:
Given that,
Original volume of balloon (V1) = 0.3L
Original temperature of balloon (T1) = 25.0°C
[Convert 25.0°C to Kelvin by adding 273
25.0°C + 273 = 298K]
New volume of balloon (V2) = ?
New temperature of balloon (T2# = 275.0°C
[Convert 25.0°C to Kelvin by adding 273
275.0°C + 273 = 548K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
0.3L/298K = V2/548K
To get the value of V2, cross multiply
0.3L x 548K = 298K x V2
164.4L•K = 298K•V2
Divide both sides by 298K
164.4L•K /298K = 298K•V2/298K
0.55L = V2
Thus, the new volume of the balloon would be 0.55 litres