Question

In ΔBCD, the measure of ∠D=90°, BD = 63, CB = 65, and DC = 16. What ratio represents the cosine of ∠B?

Answer 1

63/65

Explanation:

Just did on delta math

Answer 2

`Cos \angle B=(63)/(13)`

Explanation:

-Given that ΔBCD is a right triangle with ∠D=90° as in the attached figure.

-The ratio of Cos of ∠B can be obtained using the right triangle identities:

`Cos \ \theta=(Adjacent)/(Hypotenuse)\\\\Cos \ B=(63)/(16)`

Hence, the cosine of ∠B can be represented by the ratios
`Cos \angle B=(63)/(13)`