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What is the energy of a photon with a frequency of 3. 6 × 1015 hz? planck’s constant is 6. 63 × 10–34 j•s.

User KatGaea
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1 Answer

10 votes

Answer:

2.029×10^-18 J

Step-by-step explanation:

E=hv

so

E=(3.06×10^15)*(6.63×10^-34)

E=2.029×10^-18 J

User Gere
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