Answer:
see below
Explanation:
f(x) = a(x-h)^2 + k
Where (h,k) is the vertex
f(x) = 9(x-5)^2 + 6. has a vertex of (5,6)
f(x) = 6(x- -9)^2 + -5 has a vertex of (-9, -5)
f(x) = 9(x- -5)^2 + -6 has a vertex of (-5, -6)
f(x) = 5(x- 6)^2 + 9 has a vertex of (6, 9)
f(x) = 6(x- 5)^2 + -9 has a vertex of (5, -9)