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What is the perimeter of a rectangle with a length of 15 ft and a width of 32 ft

User Terryann
by
3.5k points

2 Answers

3 votes
its always lengthx2 plus widthx2
(L2+ W2)

15x2= 30
32x2= 62

30+62= 92ft
User Wiml
by
3.4k points
4 votes

Answer:

94 ft

Explanation:

A rectangle shares 2 congruent lengths & 2 congruent width sides.

The perimeter is the total measurement of all sides added together. Solve:

2(15) + 2(32) = 30 + 64 = 94

94 ft is your answer.

~

User Miketucker
by
3.3k points