Question

A sample of SO2 gas has a volume of 1.16 L at a temperature of 23°C. At what temperature will the gas have a volume of 1.25 L?

Answer 1

46 degrees C

Step-by-step explanation:

We use Charles' Law:
`(V_1)/(T_1) = (V_2)/(T_2)` , where V is the volume and T is the temperature in Kelvin.

Here, V_1 = 1.16 L and T_1 = 23 + 273 = 296 K. Also, V_2 = 1.25 L. Plugging these into the equation, we have:

`(1.16)/(296) =(1.25)/(T_2)`

Cross-multiplying, we have:

1.16
`T_2` = 1.25 * 296 = 370 ⇒
`T_2` = 370/1.16 ≈ 319 K

We want to convert this back to Celsius, so we just subtract 273 from 319:

319 - 273 = 46 degrees Celsius.

Hope this helps!