Question

Find the equation of the line that is perpendicular to y = 2 3 x – 13 and passes though the point (4, –1). A) y = 2 3 x – 5 B) y = 3 2 x – 5 C) y = – 2 3 x + 5 D) y = – 3 2 x + 5

Answer 1

the answer is D. y= _ 3 2 x + 5

Explanation:

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Answer 2

The answer to your question is the letter D.

Explanation:

Data

Perpendicular to y = 2/3 x - 13

Point = (4, -1)

Process

1.- Determine the slope of the original line. The slope is the coefficient of the x.

y = 2/3 x - 13

slope = 2/3

2.- Determine the slope of the perpendicular line. The new slope is the reciprocal.

new slope = -3/2

3.- Find the equation of the new line

(y + 1) = -3/2(x - 4)

-Simplify

y + 1 = -3/2x + 6

y = -3/2x + 6 - 1

4.- Result

y = -3/2x + 5