Question

15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl calculated in grams?

Answer 1

41.56 g

Step-by-step explanation:

Given data:

Mass of NH₄Cl = 15.50 g

Actual yield of AgCl = 35.50 g

Theoretical yield of AgCl = ?

Solution:

Chemical equation:

NH₄Cl + AgNO₃ → AgCl + NH₄NO₃

Number of moles of NH₄Cl:

Number of moles = mass/ molar mass

Number of moles = 15.50 g/ 53.491 g/mol

Number of moles = 0.29 mol

Now we will compare the moles of NH₄Cl with AgCl .

NH₄Cl : AgCl

1 : 1

0.29 : 0.29

Theoretical yield of AgCl:

Mass = number of moles × molar mass

Mass = 0.29 mol ×143.32 g/mol

Mass = 41.56 g