Question

1 point

Dudley's Trophy Shop charges $4 per line for engraving plus a $36 set up
charge for the team logo. The following equation is used to find C, the total
charge for a trophy order with n lines of engraving: C-36+4n Which
equation is equivalent when solved for n in terms of c?
On=4(C-36)
On=C-36
O n= (C/4) -9
On= (C/4) +9

Answer 1

n= (C/4) -9

Explanation:

The equation that in this problem describes the total charge for a trophy order with n lines of engraving is:

`C=36+4n`

where

n is the number of lines of engraving

We want to re-arrange the equation to solve for n in terms of C. To do that, we proceed as follows:

1) First, we subtract 36 from both sides of the equation. We get:

`C-36 = 36-36+4n\\C-36=4n`

2) Now, we divide by 4 both sides of the equation. We get:

`(C-36)/(4)=(4n)/(4)\\\rightarrow n=(C-36)/(4)`

3) Finally, we divide each of the terms on the right by 4. We get:

`n=(C)/(4)-(36)/(4)\\\rightarrow C=(C)/(4)-9`

So the correct answer is

n= (C/4) -9