Question

What is the equation of this cricle?

A. (x - 1)2 + (y - 3)2 = 4
B. x2 + (y-3)2 = 16
C. x2 + (y + 3)2 = 16
D. (x - 3)2 + y2 = 16

Answer 1

`\huge\boxed{B.\ x^2+(y-3)^2=16}`

Explanation:

The equation of a circle:

`(x-h)^2+(y-k)^2=r^2`

where

`(h,\ k)` - center

`r` - radius

From the graph we have

center - (0, 3) → h = 0, k = 3

radius - r = 4

Substitute:

`(x-0)^2+(y-3)^2=4^2\\\\x^2+(y-3)^2=16`