Question

Given rhombus TURN , with angle T measuring 60 degrees and the side length equal to 10 cm, calculate the area of the rhombus. Leave your answer in simplest radical form.

Answer 1

Area of the rhombus is
`50√(3)` =
`86.6` cm^2

Explanation:

Given:

A rhombus TURN with angle T measures 60 degrees.

Side length of the rhombus = 10 cm

Note:

Whenever a side length (
`s`) and an angle (
`\theta`) of the rhombus were given.

Its area = (s)^2 sin(
`\theta`)

Area of the rhombus :

⇒
`A=(s)^2* sin(\theta)`

⇒
`A=(10)^2* sin(60)`

⇒
`A=100* sin(60)`

⇒
`A=100(√(3) )/(2)`

⇒
`A=50√(3)` cm^2

So,

The area of the rhombus is 50*sq-rt(3) cm^2