Question

Given the reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 607.3 kJ XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = + 356.9 kJ what is Δ H for this reaction? X ( s ) + 1 2 O 2 ( g ) + CO 2 ( g ) ⟶ XCO 3 ( s )

Answer 1

The answer to your question is ΔH = -964.2 kJ

Step-by-step explanation:

Data

Reaction 1 X + 12O₂ ⇒ XO ΔH = -607.3 kJ

Reaction 2 XCO₃ ⇒ XO + CO₂ ΔH = 356.9 kJ

ΔH for Reaction 3 X + 12O₂ + CO₂ ⇒ XCO₃

Process

1.- Write the Reaction 1 the same

2.- Invert the order of reaction 2, and change the sign of the Enthalpy

Reaction 1 X + 12O₂ ⇒ XO ΔH = -607.3 kJ

Reaction 2 XO + CO₂ ⇒ XCO₃ ΔH = - 356.9 kJ

3.- Sum up the reactions

X + 12O₂ + XO + CO₂ ⇒ XO + XCO₃

4.- Simplify

X + 12O₂ + CO₂ ⇒ XCO₃ ΔH = -964.2 kJ