Answer:
Approximately 63 business students must be randomly selected to estimate the mean monthly earnings of business students at one college
Explanation:
confidence interval = 95%
Standard deviation
= 569
= 1 - 0.95 = .05
=
= 1.96
We want 95% confidence that the sample mean is within $140 of the population mean
margin of error ( E ) =140
let n be the sample size
margin of error ( E ) =
![Z_{(\alpha )/(2)}(\sigma )/(√(n))](https://img.qammunity.org/2021/formulas/mathematics/college/11va410rwsq1ew3dklhqcwmpi23r9fzquc.png)
squarring both side
![E^(2) = 1.96^(2)*(\sigma ^(2))/(n)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5avul8r2moc2s64gdhhu9w3riv33kxwia5.png)
![n = (1.96^(2))/(140^(2))* 569^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/r3v813w0eyy8h1486ufzhw3uyqan5j4yxf.png)
n = 63.45
n =63 approximately