Question

Please help asap with this question.

Answer 1

Answer is given below with explanations.

Explanation:

`given \: in \: a \: triangle \: \\ AC = 11 \: ft \: \: and \: angle \: B = 45 \: degrees \\ to \: find \: BC \: we \: use \: sin \: theta \\ we \: know \: sin \: theta = (opposite \: side)/(hypotenuse) \\ here \: theta \: = 45 \: degrees \\ sin(45) = (11)/(BC) \\ (1)/( √(2) ) = (11)/(BC) \\ BC = 11 √(2)`

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