Question

A 12.0g sample of a substance requires 50.9 J to raise its temperature by 6.00 c. What is it’s specific heat

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}`

Let's find the specific heat of sample using given formula :

`\qquad \tt \dashrightarrow \:Q = m \: s \triangle T`

where,

• Q = heat transfer

• m = mass

• S = specific heat

• 
  `\tt \triangle T` = change in temperature

`\qquad \tt \dashrightarrow \:50.9 = 12 * \: s * 6`

`\qquad \tt \dashrightarrow \:s = (50.9)/(72)`

`\qquad \tt \dashrightarrow \:s = 0.707 \:`

Therefore, specific heat of that substance is 0.707 J/g°C