Question

A car dealer has 10 salespersons. Each salesperson keeps track of the number of cars sold each month and reports it to the management at the end of the month. The management keeps the data in a file and assigns a number, 1 to 10, to each salesperson. The following statement declares an array, cars, of 10 components of type int to store the number of cars sold by each salesperson.

Write the code to store the number of cars sold by each salesperson in the array cars, output the total numbers of cars sold at the end of each month, and output the salesperson number selling the maximum number cars. (Assume that data is in the file cars.dat, and this file has been opened using the ifstream variable inFile.)

Answer 1

To store the number of cars sold by each salesperson in the array cars, use a loop to read the data from the file. Output the total number of cars sold at the end of each month using another loop. Determine the salesperson number selling the maximum number of cars by keeping track of the index of the maximum element.

Step-by-step explanation:

To store the number of cars sold by each salesperson in the array cars, you can use a loop to read the data from the file and assign it to the array. Here is the code:

int cars[10];
for (int i = 0; i < 10; i++) {
inFile >> cars[i];
}

To output the total number of cars sold at the end of each month, you can use another loop to calculate the sum of all elements in the array. Here is the code:

int totalCarsSold = 0;
for (int i = 0; i < 10; i++) {
totalCarsSold += cars[i];
}
cout << "Total cars sold: " << totalCarsSold << endl;

To determine the salesperson number selling the maximum number of cars, you can keep track of the index of the maximum element as you iterate through the array. Here is the code:

int maxCarsSold = cars[0];
int maxIndex = 0;
for (int i = 1; i < 10; i++) {
if (cars[i] > maxCarsSold) {
maxCarsSold = cars[i];
maxIndex = i;
}
}
cout << "Salesperson number selling the maximum number of cars: " << (maxIndex + 1) << endl;

Answer 2

To store sales data in the array 'cars', read values from 'cars.dat' and use loops to calculate the total number of cars sold and identify the top salesperson. The values are summed and compared to find the maximum sales.

Step-by-step explanation:
To store the number of cars sold by each salesperson in the array cars, initialize the array and use an input file stream to read the data from cars.dat. To calculate the total number of cars sold at the end of each month and output the salesperson selling the maximum number of cars, iterate over the array, summing the number of cars and tracking the index of the maximum value. Below is the pseudocode for the required operations:

int cars[10]; // Array to store the number of cars sold
int totalCarsSold = 0; // Variable to keep track of the total
int maxCars = 0; // Variable to store the maximum number of cars sold
int topSalesperson = -1; // Salesperson number with the maximum sales

// Reading the number of cars sold from the file
for (int i = 0; i < 10; i++) {
inFile >> cars[i];
totalCarsSold += cars[i];
if (cars[i] > maxCars) {
maxCars = cars[i];
topSalesperson = i + 1; // +1 because salesperson numbers start at 1
}
}

// Outputting the total number of cars sold
cout << "Total cars sold: " << totalCarsSold << endl;
// Outputting the top salesperson
cout << "Top salesperson: Salesperson " << topSalesperson << " with " << maxCars << " sales." << endl;

This pseudocode demonstrates the logic needed to achieve the student's goals. In practice, this code would need to be implemented in a programming language such as C++ and correctly handle file operations including opening and closing the cars.dat file.