Answer:
the vertex is at (2, 8) and the axis of symmetry is x = 2
Explanation:
In h(x)=−2x2+8x please use the symbol " ^ " to indicate exponentiation:
h(x)=−2x^2+8x
This is a quadratic equation with coefficients a = -2, b = 8 and c = 0.
The axis of symmetry equation is x = -b/ (2a).
-8
Here, with a = -2 and b = 8, the axis of symmetry is x = --------- = 2
2(-2)
To find the y-coordinate of the vertex, substitute 2 for x in h(x)=−2x^2+8x, obtaining
h(2) = -2(2)^2 + 8(2) = -2(4) + 16 = 8
In summary, the vertex is at (2, 8) and the axis of symmetry is x = 2.