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What quantity of gas, in moles, is contained in 26.97L at STP?

User Mderk
by
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1 Answer

4 votes

Answer:

The answer to your question is 1.09 moles

Step-by-step explanation:

Data

Volume = 26.97 l

Temperature = 20°C

Pressure = 1 atm

Gas constant = 0.082 atm l / mol°K

Process

1.- Convert temperature to °K

Temperature = 26.97 + 273

= 299.97°K

2.- Write the formula

PV = nRT

-solve for moles

n = PV /RT

-substitution

n = (1 x 26.97) / (0.082 x 299.97)

-Simplification

n = 26.97 / 24.6

-Result

n = 1.09

User Tetris
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