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A teacher has 30 students in a classroom. She has 6 seats in the front row. How many ways can she arrange her students to sit in the front row?

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Answer:

427,518,000 ways.

Explanation:

-This is a permutation problem of the form:


P(n,r)=(n!)/((n-r)!)

Where n is the number of objects and r is the number of objects taken at a time.

-Permutation is a linear order or sequence arrangement of a set's elements.

-The number of ways can therefore be calculated as:


P(n,r)=(n!)/((n-r)!)\\\\\\=(30!)/((30-0)!)\\\\\\=427,518,000

Hence, the 30 students can be arranged in 427,518,000 different ways.

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