Question

A sample of fluorine gas occupies 0.810 L at 270 K and 1 atm. What volume does the gas occupy when the pressure is doubled, and the temperature increases to 400 K?

Answer 1

V₂ = 0.6 L

Step-by-step explanation:

Given data:

Initial volume of gas = 0.810 L

Initial temperature = 270 K

Initial pressure = 1 atm

Final volume = ?

Final pressure = 2 atm

Final temperature = 400 K

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 1 atm × 0.810 L × 400 K / 270 K × 2 atm

V₂ = 324 atm .L. K / 540 atm.K

V₂ = 0.6 L