Question

Write the quadratic equation whose coefficient with x^2 equal to 1 and roots are:

Answer 1

Explanation:

if a,b are the roots of a quadratic eq. with coefficient of leading term is 1 ,then

(x-a)(x-b)=1

here roots are
`Here~roots~are~(√(3) -1)/(2)} ~and~(√(3)+1 )/(2) \\reqd. ~eq.~is~[x-(√(3) -1)/(2) ][x-(√(3)+1)/(2) ]=0\\or~[(x-(√(3))/(2) })+(1)/(2) ][(x-(√(3))/(2)) -(1)/(2)]==0\\or~(x-(√(3))/(2) )^2-((1)/(2) )^2=0\\or~x^2-√(3) x+(3)/(4)-(1)/(4)=0\\or~ x^2-√(3)x+(1)/(2) =0`