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How many moles of Ag will be produced from 46.0 g of Cu, assuming AgNO3 is available in excess?

User Kelloti
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Answer:

1.44 mol

Step-by-step explanation:

Given data:

Mass of Cu = 46 g

Moles of Ag produced = ?

Solution:

Chemical equation:

Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂

Number of moles of Cu:

Number of moles = mass/ molar mass

Number of moles = 46 g/63.546 g/mol

Number of moles = 0.72 mol

Now we will compare the moles of Cu and silver from balance chemical equation:

Cu : Ag

1 : 2

0.72 : 2×0.72 = 1.44 mol

Thus from 46 g of Cu 1.44 moles of Ag is produced .

User Chvanikoff
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